answered question 10/13/2009 The Perimeter Of A Rhombus Whose Big Diagonal Measures 18cm And Small Diagonal Measures 9cm? Perimeter of a rhombus=4s(4*side)diagonals intersect at midpoints(o) and they form right angles...BC^2=BO^2+CO^2 =9^2+18^2 =81+324 =405BC=√405cms(can do further simplification)
