The sum of 3 consecutive numbers is 147 so, X      (first interger)      X+1   (second)      X+2   (third) *combine like terms X+X+1+X+2=147 3x+3=147     -3   -3 3X=144 /3    /3 X=48 (substitute 48 for x) 48+1=49 48+2=50 So the intergers are 48, 49, and 50. … Read more